48 lines
1.8 KiB
Python
48 lines
1.8 KiB
Python
"""
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用户模型
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"""
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from sqlalchemy import Column, String, DateTime, func
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from sqlalchemy.dialects.mysql import CHAR
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from sqlalchemy.orm import relationship
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from app.core.database import Base
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import uuid
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class User(Base):
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"""用户表"""
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__tablename__ = "users"
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id = Column(CHAR(36), primary_key=True, default=lambda: str(uuid.uuid4()), comment="用户ID")
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username = Column(String(50), unique=True, nullable=False, comment="用户名")
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email = Column(String(100), unique=True, nullable=False, comment="邮箱")
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password_hash = Column(String(255), nullable=False, comment="密码哈希")
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role = Column(String(20), default="user", comment="角色: admin/user（保留字段，用于向后兼容）")
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created_at = Column(DateTime, default=func.now(), comment="创建时间")
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updated_at = Column(DateTime, default=func.now(), onupdate=func.now(), comment="更新时间")
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# RBAC关系（多对多）
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roles = relationship("Role", secondary="user_roles", back_populates="users")
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def __repr__(self):
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return f"<User(id={self.id}, username={self.username})>"
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def has_permission(self, permission_code: str) -> bool:
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"""检查用户是否有指定权限"""
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# 如果是admin，拥有所有权限
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if self.role == "admin":
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return True
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# 检查用户的所有角色是否包含该权限
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for role in self.roles:
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for permission in role.permissions:
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if permission.code == permission_code:
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return True
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return False
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def has_role(self, role_name: str) -> bool:
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"""检查用户是否有指定角色"""
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# 如果是admin，拥有所有角色
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if self.role == "admin":
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return True
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return any(role.name == role_name for role in self.roles) |